Составить ур-я реакций: а)ch4- c2h2- ch3-coh- - вопрос №3496415422332 от vadimbukov 25.05.2020 04:27

Question

Химия: Составить ур-я реакций: а)ch4- c2h2- ch3-coh- ch3-ch2oh- ch3-ch2-br- c2h4- ch3-ch2oh- ch3-coh б)ch4- hcoh- ch3oh- ch3cl- c2h6- c2h5oh- ch3cooh ! : )

vadimbukov · Answer

CH₄ = CHΞCH + H₂
CHΞCH + H₂O = CH₃CHO
CH₃CHO + H₂ = CH₃-CH₂OH
CH₃-CH₂OH + HBr = CH₃-CH₂-Br + H₂O
CH₃-CH₂-Br + NaOH(спирт) = CH₂=CH₂ + NaBr + H₂O
CH₂=CH₂ + H₂O = CH₃-CH₂-OH
CH₃-CH₂-OH = CH₃-CHO + H₂

CH₄ + O₂ = CH₂O + H₂O
HCOH + H₂ = CH₃OH
CH₃OH + HCl = CH₃Cl + H₂O
2CH₃Cl + 2Na = CH₃-CH₃ + 2NaCl
CH₃-CH₃ + Cl₂ = CH₃-CH₂Cl + HCl
CH₃-CH₂Cl + NaOH = CH₃-CH₂-OH + NaCl
5CH₃-CH₂-OH + 4KMnO₄ + 6H₂SO₄ = 5CH₃-COOH + 2K₂SO₄ + 4MnSO₄ + 11H₂O

Составить ур-я реакций: а)ch4-> c2h2-> ch3-coh-> ch3-ch2oh-> ch3-ch2-br-> c2h4-> ch3-ch2oh-> ch3-coh б)ch4-> hcoh-> ch3oh-> ch3cl-> c2h6-> c2h5oh-> ch3cooh ! : )