Нужно рассчитать массовую долю элементов: 1.h2so4 2.hno3 3.h2co3 4.kmno4 5.k2c2o7

1)M(h2so4) = 98 г/моль
w(h)=(2/98)*100=2.04%
w(s)=(32/98)*100=32.65%
w(o)=(64/98)*100=65.31%

2)M(HNO3)=63 г/моль
w(h)=(1/63)*100=1.59%
w(n)=(14/63)*100=22.22%
w(o)=(48/63)*100=76.2%

3)M(H2CO3)=62 г/моль
w(h)=(2/62)*100=3.23%
w(c)=(12/62)*100=19.05%
w(o)=(48/62)*100=77.42%

4)M(KMnO4)=158 г/моль
w(K)=(39/158)*100=24.96%
w(Mn)=(55/158)*100=34.81%
w(o)=(64/158)*100=40.51%

5)M(K2C2O7)=214 г/моль
w(K)=(78/214)*100=36.45%
w(c)=(24/214)*100=11.215%
w(o)=(112/214)*100=52.34%