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Построить отрезки АВ и СD и найти координаты их точки пересечения, если
А (-3;4), В (2;-1), С (-1; -2), D (4;3).
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Уравнение прямой проходящей через точки С (-1; -2) и D (4;3).
y - y₁ =( (y₂ - y₁)/(x₂-x₁) )*( x - x₁) ; k = (y₂ - y₁)/(x₂-x₁)
y - 4 = ( (-1 -4) / (2 -(-3) ) *( x - (-3) ) ;
y - 4 = - ( x +3) ;
y = - x +1 . (1)
- - - - - - -
Уравнение прямой проходящей через точки С (-1; -2) и D (4;3).
y -(-2) =( (3 -(-2) )/(4 - (-1) )*( x - (-1) ) ;
y + 2 = x + 1 ;
y = x - 1 . (2)
Решая совместно уравнения (1) и (2) получим точку пересечения P
AB и CD
{ y = -x +1 ;
{ y = x -1 . - x + 1 =x - 1 ⇒ x = 1
y = - x +1 = -1+1 = 0 || y = x-1 =1 -1 = 0 ||
ответ : P (1 ; 0)
