Число 1/5 в 100 степені записали у вигляді скінченого десяткового дробу. Знайдіть останню цифру цього запису

Дано:

L=8 см

∠β = 30°

Найти:

V=?

S=?

Обычно, в треугольной пирамиде проекция бокового ребра на основание равна две третьих высоты. (2/3)*h (это высота основания пирамиды).

1) (2/3)*h=8*cos 30°=8√3/2=4√3 см

2) Высота основания h=(3/2)*4√3=6√3 см

3) а=h/cos 30°=6√3/(√3/2)=12 см (Сторона основания)

4) Н= L*sin 30°=8*(1/2)=4 см (Высота пирамиды)

5) А=√(Н² + (h/3)²)=√(16 + (6√3/3)²)=√(16 + 12)=√28=2√7≈5,292 см (Апофема "А" боковой грани)

6) S1=a²√3/4=12²√3/4=36√3≈62,3538 см² (Площадь основания)

7) S2=(1/2)РА=(1/2)*(3*12)*(2√7)=36√7 ≈ 95,25 см². (Площадь боковой поверхности)

8) S=S1+S2=62,3538+95,247=157,6008 см² (Вся поверхность)

9) V=(1/3)SoH=(1/3)*62,3538*4=83,1384 см³

ответ: S=157,6008 см², V=83,1384 см³.

                                  Стеллерова или морская корова!The black book of extinct animals and describes another species, discovered during the expedition of Vitus Bering in 1741. His ship called the "St. Peter" was wrecked near the coast of the island, later named after its discoverer. The team was forced to stay here for the winter and to eat unusual animals called cows due to the fact that they were eating sea grass. These creatures were huge and slow. Their weight often reaches ten tons. The meat of the sea cow was very tasty and useful. Hunting on these harmless giants had not been difficult, as the animals calmly eating algae close to the coast, were not able to escape in the depth and wasn't afraid of the man. In the end, after the expedition to the Islands of profit brutal hunters who killed all the population of the sea cows for some three decades