Doira yuzi 81 taxsim p ga teng bo lsa shu aylanani - вопрос №1626895881 от danlis2003 01.03.2022 07:42

Question

Математика: Doira yuzi 81 taxsim p ga teng bo lsa shu aylanani uzunligini toping​

danlis2003 · Answer

[tex]rac{m^2-25}{m^2+10m+25} =rac{(m-5)(m+5)}{(m+5)^2}=rac{m-5}{m+5}[/tex][tex]rac{m^2+10m+25}{25-m^2} =rac{(m+5)^2}{(5-m)(5+m)}=rac{m+5}{5-m}[/tex][tex]rac{m^2-10m+25}{m^2-25}=rac{(m-5)^2}{(m-5)(m+5)}=rac{m-5}{m+5}[/tex][tex]rac{25-m^2}{m^2-10+25}=rac{m+5}{m-5}[/tex]5.[tex]rac{5(a-5)}{a^2-25}=rac{5}{a+5}[/tex]при a=-4,5 [tex]rac{5}{a+5}= rac{5}{0,5}= 10[/tex][tex]rac{9a^2-6+1}{6a-2} = rac{9 a^{2} - 5}{6 a - 2}=rac{3 a}{2} + rac{1}{2} - rac{2}{3 a - 1}[/tex]при...

Doira yuzi 81 taxsim p ga teng bo'lsa shu aylanani uzunligini toping​

Doira yuzi 81 taxsim p ga teng bo'lsa shu aylanani uzunligini toping