Найдите и постройте эмпирическую функцию распределения данной выборки (фото)

Today, I am at home. It is Saturday morning and it is very cold. Last month, my family and I were on

holiday in Canada. The weather is fantastic! It is really hot and sunny. We were happy then

The last vacation was great, but now I am

happy to be back. It is nice to be with all my friends.

Twenty years ago, there were no cars on the street where I lived.There was only one bakery in the whole town. There was no Internet at that time, so we sent letters to communicate with friends and family who lived far away. I didn't like to go to school far away because, the bus stop was from my house. Now, the street in front of my house.

There are many cars and buses. There are also many shops and there is big a department store right next to my house!

Yesterday, there was police blockade on the road because there was a robbery. I was

very scared and my parents worried because it happened in front of my house. This

morning, I heard that the robber got caught and I am glad that finally our place is safe!

1) Работаем по рис..

S полн.= S осн + S бок

S осн = √(р·(р-а)(p-b)(p-c)) ,где р - полупериметр:

р= (a+ b+ c)/2 = (10+10+12)/2 = 16, тогда 

S осн = √(р·(р-а)(p-b)(p-c))= √(16·6·6·4) =4·6·2= 48 ( см²).

2) Если боковые грани наклонены к плоскости основания под одним углом,

то площадь боковой поверхности равна половине произведения периметра

основания на высоту боковой грани: S бок = P осн·SH = 32·SH =... 

Если боковые грани наклонены к плоскости основания под одним углом, то
в основание пирамиды можно вписать окружность, причём вершина пирамиды

проецируется в её центр, т.е. НО = r = Sосн/ p=48/16= 3 (см) 

Из ΔSOH - прям.: L SHO = 45⁰, тогда L SHO = 45⁰, значит ΔSHO - равнобедрен.

и SO=ОН=3 см, SH = 3√2 см .

S бок = P осн·SH = 32·SH = 32·3√2 = 96√2 (см²)

Таким образом S полн = 48 + 96√2 = 48(1+ 2√2) (см²).