Как решить линейное уравнения: 1/3х=12, -4х=1/7, 1/6y=1/3

1)



2)



3)

1) 1/3 х = 12
х = 12/  1/3 = 12* 3/1
х = 36
2) - 4х = 1/7
х = 1/7  / (-4) = 1/(7 * (-4)) = - 1/28
х = - 1/28
3) 1/6у = 1/3
у = (1/3) / (1/6) = (1/3) / (6/1)
у = 2