В)10,02*5-(44-(34,5+7,87)): 0,05= г)3,36: 3,2+(4-(7-6,3)*4,2)-1,1= - вопрос №199347210025443457870053363247634211 от 2a0n0u5g 23.10.2021 01:06

Question

Математика: В)10,02*5-(44-(34,5+7,87)): 0,05= г)3,36: 3,2+(4-(7-6,3)*4,2)-1,1=

2a0n0u5g · Answer

В)10,02*5-(44-(34,5+7,87)):0,05=17.51)34.5+7.87=42.372)44-42.37=1.633)1.63:0.05=32.64)10.02*5=50.15)50.1-32.6=17.5г)3,36:3,2+(4-(7-6,3)*4,2)-1,1=1.011)7-6.3=0.72)0.7*4.2=2.943)4-2.94=1.064)3.36:3.2=1.055)1.05+1.06=2.116)2.11-1.1=1.01...