пума060
09.07.2022 06:13

До площини, якій належить квадрат ABCD, через вершину B проведений відрізок KB так, що KB⊥AB і KB⊥BC. Сторона квадрата 16 см, а довжина відрізка KB= 30 см. Знайди синус лінійних кутів α і β між площиною квадрата і площинами KAD і KCD.

Відповідь введи у вигляді не скороченого дробу:


До площини, якій належить квадрат ABCD, через вершину B проведений відрізок KB так, що KB⊥AB і KB⊥BC

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Ответ:
Raz1elGG
17.04.2020 10:05
I think summer is the best season of all because it is warm, the nature is beautiful and we have great opportunities for rest. Summer is a time of holidays. We can go anywhere, spend our time near a river or a lake on fresh, green grass, swim in warm water, or climb mountains, play different games, ride a bicycle and so on.I spend my summer holidays at my granny’s. There are many things there to do. What I did most of the time - I swam in the sea and sunbathed. Sometimes I made a fire with my friends at the seaside and cooked potatoes there. It was wonderful. We told anecdotes to each other, and did everything we wanted. I also got used to walk alone in the forest.When August was coming to its end, I went on a small voyage by ship. The ship name was “Sevastopol”.But this summer wasn’t for me only sugar and honey. I have passed through the graduating exams after school and entering exams in the university. So the bigger part of my summer vacations I spent sitting with the books. Of course, it was not interesting, but I’m glad that I did it because now I’m a student of the best university in our country.
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Ответ:
pashaShum12345
15.01.2020 07:33

3,557+x=4*23,557+x=4∗2

3,557+x=83,557+x=8

x=8-3,557x=8−3,557

x=4,443x=4,443

2)\;\tt\displaystyle\frac{x-0,731}{3}=52)

3

x−0,731

=5

x-0,731=5*3x−0,731=5∗3

x-0,731=15x−0,731=15

x=15+0,731x=15+0,731

x=15,731x=15,731

\begin{gathered}3)\;\tt\displaystyle\frac{12,392+x}{5}=2,365+2,635\\\end{gathered}

3)

5

12,392+x

=2,365+2,635

\tt\displaystyle\frac{12,392+x}{5}=5

5

12,392+x

=5

12,392+x=5*512,392+x=5∗5

12,392+x=2512,392+x=25

x=25-12,392x=25−12,392

x=12,608x=12,608

\begin{gathered}4)\;\tt\displaystyle\frac{125,95-x}{2.65+4,35}=6\\\end{gathered}

4)

2.65+4,35

125,95−x

=6

\tt\displaystyle\frac{125,95-x}{7}=6

7

125,95−x

=6

125,95-x=6*7125,95−x=6∗7

125,95-x=42125,95−x=42

x=125,95-42x=125,95−42

x=83,95x=83,95

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