5целых 1/3: (9-7целых 2/3)+(11 целых 1/3 -6 целых - вопрос №23314765139723111363711314 от TitikØ 30.03.2022 16:19

Question

Математика: 5целых 1/3: (9-7целых 2/3)+(11 целых 1/3 -6 целых 3/7: 1 целая 13/14)=

TitikØ · Answer

5_1/3:(9-7_2/3)+(11_1/3 -6_3/7:1_13/14)= 12
2 1 5 4 3

1) 9-7_2/3 = 8_3/3 - 7_2/3 = 1_1/3
2) 5_1/3 : 1_1/3 = 16/3 * 3/ 4 = 4
3) 6_3/7 : 1_13/14 = 45/7 * 14/27 = (45*14) / (7*27) = 5*2 / 3 = 10/3 = 3_1/3
4) 11_1/3 - 3-1/3 = 8
5) 4+8 = 12