(7a++3)=5 (8у+11)-13=9y-5 3y-(5-y)=11 5x+(3x-7)=9 - вопрос №2818254735811139535115379953474531022 от yananesteshl 11.03.2022 14:23

Question

Математика: (7a++3)=5 (8у+11)-13=9y-5 3y-(5-y)=11 5x+(3x-7)=9 9x+5y-34=74 5x-3y+10=22

yananesteshl · Answer

1)(7а+1)-(6а+3)=57а+1-6а-3=5а=5-1+3=72)(8у+11)-13=9y-5 8у-9у=-5-11+13-у=-3у=33)3y-(5-y)=113у+у=11+54у=16у=44)5x+(3x-7)=95х+3х=9+78х=16х=25)9x+5у-34=745у=-9х+74+34=-9х+108у=-1,8х+21,66)5x-3y+10=223у=5х-12у=1 2/3х-4...