31100-(4180*3+236*8)= (2600-2320)/4+140*3 5110*6-99/33= - вопрос №3336477311004180323682600232041403511069933813057224715 от dilinur15 18.03.2022 12:27

Question

Математика: 31100-(4180*3+236*8)= (2600-2320)/4+140*3 5110*6-99/33= 8130*5+72/24= 7150*6-70/14=

dilinur15 · Answer

7150 * 6 – 70 / 14 = 428957150*6=42900 70/14=5 42900-5=42895 8130 * 5 + 72 / 24 = 406538130*5=4065072/24=340650+3=406535110 * 6 – 99 / 33 = 306575110*6=3066099/33=330660-3=30657(2600 – 2320) / 4 + 140 * 3 = 4902600-2320=280280:4=70140*3=420 70+420 = 49031100-(4180*3+236*8)=1667214180×3=12540 236×8=188812540+1888=1442831100-14428=16672...