Решить 4-(2/5+7/18) 2-(11/19+15/38) 5-(2/5+5/14) 7-(19/40+1/3) - вопрос №34411444257182111915385255147194013 от sofia27supko 13.10.2020 10:38

Question

Математика: Решить 4-(2/5+7/18) 2-(11/19+15/38) 5-(2/5+5/14) 7-(19/40+1/3)

sofia27supko · Answer

4 - (2/5 + 7/18) = 3 19/901) 2/5 + 7/18 = 36/90 + 35/90 = 71/902) 4 - 71/90 = 3 19/902 - (11/19 + 15/38) = 1 1/381) 11/19 + 15/38 = 22/38 + 15/38 = 37/382) 2 - 37/38 = 1 1/385 - (2/5 + 5/14) = 4 17/701) 2/5 + 5/14 = 28/70 + 25/70 = 53/702) 5 - 53/70 = 4 17/707 - (19/40 + 1/3) = 6 23/1201) 19/40 + 1/3 = 57/120 + 40/120 = 97/1202) 7 - 97/120 = 6 23/120...