А) -(7-3у)=8-8(2-у) б) -5(2-2х)=2(х-3)+4 в) 2х-4(х+7)=3(2-х) - вопрос №34564427388252223424732 от nubpolymaster 12.12.2020 10:39

Question

Математика: А) -(7-3у)=8-8(2-у) б) -5(2-2х)=2(х-3)+4 в) 2х-4(х+7)=3(2-х)

nubpolymaster · Answer

А) -(7-3y) = 8-8(2-y) -7+3y = 8-12+8y8y-3y = 12-75y = 5y = 5/5y = 1б) -5(2-2x) = 2(x-3)+4-10+10x = 2x-6+410x-2x = 10-6+48x = 8x = 8/8x = 1в) 2x-4(x+7) = 3(2-x)2x-4x-28 = 6-3x2x-4x+3x = 6+28x = 34...