Найдите корень уравнения : 1)8y-3(2y-3)=7y-2(5y+8) 2)5y+7(3-y)=3(5-2y)-6

8y-3(2y-3)=7y-2(5y+8)
8у-6у+9=7у-10у-16
2у+9=-3у-16
2у+3у=-9-16
5у=-25
у=-5

5y+7(3-y)=3(5-2y)-6
5у+21-7у=15-6у-6
4у=-21+15-6
4у=-12
у=-3