С! а)31/80 + (3/16 + 39/80) б)2/45 + (3/45 + 7/9) - вопрос №3763078318031639802453457937514114 от Klinyushina 11.01.2020 08:25

Question

Математика: С! а)31/80 + (3/16 + 39/80) б)2/45 + (3/45 + 7/9) в)(3/7 + 5/14) + 1/14.

Klinyushina · Answer

A) 31/80 +(3/16 + 39/80)= (31/80+39/80)+3/16=70/80+3/16=14/16+3/16=17/16=1 1/16б) 2/45+(3/45+7/9)=(2/45+3/45)+7/9=5/45+7/9=1/9+7/9=8/9в) (3/7+ 5/14)+1/14=3/7+(5/14+1/14)=3/7+6/14=3/7+3/7=6/7...