1.0,4b+3=0,2(3b+1)-b 2.3(x-1)=2(2-x)+6 3.4(3-h)-11=7(2h-5) - вопрос №41413271043023123122634311725433442 от darya2401 25.11.2022 11:28

Question

Математика: 1.0,4b+3=0,2(3b+1)-b 2.3(x-1)=2(2-x)+6 3.4(3-h)-11=7(2h-5) 4.-3(3y+4)+4(2y-1)=0 5.0,9(4y-2)=0,5(3y-4)+4,4

darya2401 · Answer

1)0.4b+3=0.6b+0.2-b
0.4b-0.6b+b=0.2-3
0.8b=2.8
b=3.5
2)3x-3=4-2x+6
3x+2x=4+6+3
5x=13
x=2.6
3)12-4h-11=14h-35
-4h-14h=-35-12+11
-18h=-36
h=2
4)-9y-12+8y-4=0
-9y+8y=12+4
-y=16
y=-16
5)3.6y-1.1=1.5y-2+4.4
3.6y-1.5y=-2+4.4+1.1
2.1y=3.5
y=3.5/2.1