Log(3)(x^2-1)=1 log(0,5)(x+2)+log(0,5)(x+3)=-2log(0,5)(x-1) - вопрос №492787632110520532051 от 79854246143TATIANA 20.01.2023 11:16

Question

Математика: Log(3)(x^2-1)=1 log(0,5)(x+2)+log(0,5)(x+3)=-2log(0,5)(x-1)

79854246143TATIANA · Answer

1) log3(2x+1)=22x+1=92x=8x=4 2)log0.2(x^2 + 4x)=-1x^2 + 4x=2x^2 + 4x - 2=0x1=V6 - 2x2=-(V6 + 2) 3)log^2 5(X) - log5(x) -2 =0(log5(X)-2)(log5(x)+1)=0x1=25x2=1/5 4) log1/3(x^2-5x+7) 0x^2-5x+7 1x^2-5x+6 0(x-6)(x+1) 0x1 6x2 -1...