C^9*c^2= b^3: b^4= (a^5)^3= (xy)^8= (b/c)^3= x^2*(x^4)^3= - вопрос №506275792345383243573 от LiraReeman 22.01.2021 14:26

Question

Математика: C^9*c^2= b^3: b^4= (a^5)^3= (xy)^8= (b/c)^3= x^2*(x^4)^3= a*a^5/a^7= (-3a^2b^5)^2= 9x^3y^4/15x^5y= решите умоляю! )

LiraReeman · Answer

C^9+2 = C^11b^3-4 = b^-1= 1/b^1a^5*3 = a^15x^8 * y^8b^3/c^3x^2 * x^4*3 = x^2 * x^ 12= x^242a^6 / a^7 = a^-1= 1/a^19a^4b^10...