Решите уравнение: log5 (4x+1)=3 log0,56(1/12x-1)=log0,56 3 lg(1-0,05x)=-1

1)log5 (4x+1) = log5 125
4x+1=125
4x=124
x=31
2)(1/12)*x-1=3
(1/12)*x=4
x=48
3)log10 (1-0.05x)=log10 0.1
1-0.05x=0.1
0.05x=0.9
x=0.9/0.05=18