(3х+7)*2=32 (2х-20)/32=6 (42+2х)/2=32 (5х-7)*5=15 - вопрос №60946963723222032642223257515132327 от pervushina245 19.06.2020 12:50

Question

Математика: (3х+7)*2=32 (2х-20)/32=6 (42+2х)/2=32 (5х-7)*5=15 (13-2х)*3=27

pervushina245 · Answer

(3х+7)*2=326x+14=326x=32-14=18x=18/6=3(2х-20)/32=62x-20=6*32=1922x=192+20=212x=212/2=106(42+2х)/2=3242+2x=32*2=642x=64-42=22x=22/2=11(5х-7)*5=1525x-35=1525x=15+35=50x=50/25=2(13-2х)*3=2739-6x=2739-27=6x12=6xx=12/6=2...