1)sin2b-sin2b*cos2b=? 2)cos4b+cos2b*sin2b=? 3)tg2b*ctg2b-cos2b=? - вопрос №6129481122224223222 от nky43939nky 14.04.2023 18:57

Question

Математика: 1)sin2b-sin2b*cos2b=? 2)cos4b+cos2b*sin2b=? 3)tg2b*ctg2b-cos2b=?

nky43939nky · Answer

Sin2B -sin2B*cos2B = sin2B(1- cos2B) = sin2B( 1-(cos^2 B-Sin^2 B) = sin2B((1-cos^2 B) +sin^2 B) = sin2B (sin^2 B + sin^2 B) = 2sinB*cosB*2sin^ B= 4sin^3 B*cosB

tg2B*ctg2B-cos2B= 1-cos^2 B +sin^2 B = sin^2 B+ sin2 B =2sin^2 B