А)(30: 27-1/3)*2 1/7+2/5-5 б)6/9*1/7 в) 1 49/9+2/5 - вопрос №76115033027132172556917149925 от olegstar74p0a994 17.05.2020 03:02

Question

Математика: А)(30: 27-1/3)*2 1/7+2/5-5 б)6/9*1/7 в) 1 49/9+2/5

olegstar74p0a994 · Answer

(30:27-1/3)*2 1/7+2/5-5 =-2 14/151) 30:27=10/9 = 1 1/92) 1 1/9-1/3=10/9-1/3=10/9-3/9=7/93) 7/9*2 1/7=7/9*15/7=15/9=5/3=1 2/34) 1 2/3+2/5=5/3+2/5=25/15+6/15=31/15=2 1/155) 2 1/15-5=31/15-75/15=-44/15=-2 14/156/9*1/7 = 2/3*1/7 = 2/211 49/9+2/5 = 58/9+2/5=290/45+18/45=308/45=6 38/45...