1)x^2+2xy=3 x-y=7 2) 2x-3=y 2y+x=-1 3)3x-5y=6 2x+3y=7 - вопрос №828893912237223213356237 от hfyvjfarioS 07.03.2021 05:41

Question

Математика: 1)x^2+2xy=3 x-y=7 2) 2x-3=y 2y+x=-1 3)3x-5y=6 2x+3y=7

hfyvjfarioS · Answer

1) x=7+y(7+y)^2+2(7+y)y=349+14y+y^2+14y+2y^2=33y^2+28y+46=0D=232y=(-28+-2sqrt(58))/6x1=7+(-28+2sqrt(58))/6x2=7+(-28-2sqrt(58))/62) 2(2x-3)+x=-15x=5x=1y=2-1=-13) x=3,5-1,5y3(3,5-1,5y)-5y=610,5-4,5y-5y=6-9,5y=-4,5y=45/95=9/19x=3,5-9/19*15/10=3,5-27/38=53/19...