Доказать, что а)число 2^333+3^222 делится на 17; б) число 2^222+3^333 делится на 31. . нужно

#1
a) (a-b)-a+m=a-b-a+m=m-b
б)-(a+b)+a-(-b+k)=-a-b+a+b-k=-k
в)-63+(-24+12)+56=-63-24+12+56 =-87+68=-19
г)87-(32-49)-87=49-32=17
д)(51-а)+(-72+а)=51-а-72+а=-21
е)-(b+2,4)-(5,7-b)+(b+4,3)=-b-2,4- 5,7+b+b+4,3=b-3,8

#2
a)5a+3(a+8)=5a+3a+24=8а+24
б)6+(5у-6)•(-2)=6-10у+12=18-10у
в)-6(1-ху)-2(3+ху)+12=-6+ху-6-ху+12=0
г)7(а-2b)+11(b-a)-(2a+3b)= 7a-14b+11b-11a-2a-3b=-6a-6b

#3
(5x+2y)b+(3y-2b)y-(5b-y)x=5bx+ 2by+3y^2 -2by - 5bx +yx =3y^2 +yx= 3• (-5)^2 +(-5)•7= 75-35=40
#4
a)9-3x-x=20
-4x=20-9
-4x=11
x=-11/4
x=-2,75
б)7=6х-19-11х
7+19=-5х
-5х=25
х=-5

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