А)2x(5x-7)=2x*2-5;b)x-4/x-5 0 - вопрос №11596239257225450 от Diana12345678910123 12.01.2023 12:57

Question

Алгебра: А)2x(5x-7)=2x*2-5;b)x-4/x-5 0​

Diana12345678910123 · Answer

X^2 (x + 5) - 25(x + 5) = 0
(x + 5)(x^2 - 25) = 0
(x + 5)(x - 5)(x + 5) = 0
(x - 5)(x + 5)^2 = 0

1)
x - 5 = 0
x = 5; 2)x^2 (x + 5) - 25(x + 5) = 0   (x + 5)* (x^2 - 25) = 0
(x + 5)^2 = 0   x x = - 5;
ответ:
- 5; 5 + 5 = 0

А)2x(5x-7)=2x*2-5;b)x-4/x-5 >0​

А)2x(5x-7)=2x*2-5;
b)x-4/x-5 >0