Log по основанию 5 (x+1) log по основанию 5 (x-3) =1 решите уравнение

log(5x-3)-log(x-1)=1 (1)
log[(5x-3)/(x-1)]=1     log(a)-log(b) = log(a/b)
[(5x-3)/(x-1)]= (10)^1 
[(5x-3)/(x-1)]= (10)
(5x-3)=10X(x-1)
5x-3 = 10x-10
-3+10 = 10x-5x
7 = 5x
5x =7
x = 7/5