Решите систему: 2x^2-3xy-y^2=0 x^2+9xy-y^2=0 - вопрос №4607290223202920 от sasha23z 13.04.2022 20:40

Question

Алгебра: Решите систему: 2x^2-3xy-y^2=0 x^2+9xy-y^2=0

sasha23z · Answer

Simplifying 4x2 + -3xy + -1y2 = 0 Reorder the terms: -3xy + 4x2 + -1y2 = 0 Solving -3xy + 4x2 + -1y2 = 0 Solving for variable 'x'. Factor a trinomial. (x + -1y)(4x + y) = 0
Simplifying x2 + -9xy + -36y2 = 0 Reorder the terms: -9xy + x2 + -36y2 = 0 Solving -9xy + x2 + -36y2 = 0 Solving for variable 'x'. Factor a trinomial. (x + -12y)(x + 3y) = 0