Преобразуйте в многочлен (1-2d)^3 (5-3y)^2 (8+5y)^2 - вопрос №7336595123532852473283 от phyf 26.10.2020 21:19

Question

Алгебра: Преобразуйте в многочлен (1-2d)^3 (5-3y)^2 (8+5y)^2 (4-7n)^3 (2+8c)^3 выражение (2-m)^3+4m (p+8)^3-16p (10+a)^2-100 (5-y)^3-y^2 (6+n)^2-n2 (7-j)^2-4 (11+k)^3-22k 4-(2+5k)^4 (6c-5)^2+60c 48y+(3y-0)^3 144q^3 -(3-11q)^3 122p+(8p-7)^3 (9d+1)^2 -18d : (

phyf · Answer

(1-2d)^3=(1-2d)(1+2d+4d2)=1+2d+4d2-2d-4d2-8d3=1-d3
(5-3y)^2=25-15y+9y2
(8+5y)^2=64+40y+25y2
(4-7n)^3=(4-7n)(16+28n+49n2)=64+112n+196n2-112n-196n2-343n3=64-343n3
(2+8c)^3=(2+8c)(4-16c+64c2)=8-32c+128c2+32c-128c2+512c3=8+512c3

(2-m)^3+4m=(2-m)(4+2m+m2)+4m=8+4m+2m2-4m-2m2-m3+4m=8-m3+4m
(p+8)^3-16p=p3+512-16p
(10+a)^2-100=100+10a+a2-100=10a-a2=a(10-a)
(5-y)^3-y^2=125-y3-y2
(6+n)^2-n2=36+6n+n2-n2=36+6n=6(6+n)
(7-j)^2-4=49-7j+j2-4=48-7j+j2
(11+k)^3-22k=1331+k3-22k