3х(2-х)(3х+1)(х-2) 3(2х-1)^2+12х (х+3)^2-(х-2)(х+2) - вопрос №749836732312321212322221321 от pervushina245 09.04.2022 07:58

Question

Алгебра: 3х(2-х)(3х+1)(х-2) 3(2х-1)^2+12х (х+3)^2-(х-2)(х+2) (х^2-1)(х+3)=(х^2+1)^2+х решите плз,!

pervushina245 · Answer

= - 3х(6х²-12х+2х-4-3х³+6х²-х²+2х)= -3х(-3х³+11х²-8х-4)=9х^4 -33х³+24х²+12х

=3(4х²-4х+1)+12х=12х² - 12х+3+12х=12х²+3=3(4х²+1)

=х²+6х+9-х²+4=6х+13

(х²-1)(х+3)=(х²+1)²+х
х³+3х²-х-3=х^4+2х²+1+х
х^4 - х³ - х²+2х+4=0