1)11+4х 2х-7 2) 5-4х ≤ 7х+5 3)14+2 (-х+7) ≤ 24-3 - вопрос №90228991114272547531427243147 от kuskova2004oziqru 07.02.2020 14:09

Question

Алгебра: 1)11+4х 2х-7 2) 5-4х ≤ 7х+5 3)14+2 (-х+7) ≤ 24-3 (х-1) 4)|х|+7 10

kuskova2004oziqru · Answer

11+4х 2х -72х -18х -95 - 4х = 7х - 50 = 11хх = 014 +2(-х+7) = 24 - 3(х-1)14 + 14 - 2х = 24+3 - 3х28 - 2х = 27 - 3х1 = -хх = 1|х| + 7 = 10|х| = 3-3 х 3...

1)11+4х > 2х-7 2) 5-4х ≤ 7х+5 3)14+2 (-х+7) ≤ 24-3 (х-1) 4)|х|+7 < 10