a = 'A , B , C , D , E , F , G , H , I , J , K , L , M , N , O , P , Q , R , S , T , U , V , W , X , Y , Z'
a = a.replace(',', '')
a = a.replace(' ', '')
for k in a:
for l in a:
for m in a:
for n in a:
print(k + l + m + n)
насчет повторов не уверен, если будут, то:
l = []
a = 'A , B , C , D , E , F , G , H , I , J , K , L , M , N , O , P , Q , R , S , T , U , V , W , X , Y , Z'
a = a.replace(',', '')
a = a.replace(' ', '')
for k in a:
for l in a:
for m in a:
for n in a:
l.append(k + l + m + n)
l = set(l)
for i in l:
print(i)
#include <iostream>
using namespace std;
int main(int argc, char** argv)
{
int a,b,s,p;
cout<<"Input a: ";
cin>>a;
cout<<"Input b: ";
cin>>b;
p = (a+b)*2;
s= a*b;
cout<<"Perimetr: "<<p<<"\nPloschad: "<<s<<endl;
}
Диагональ не знаю как.
2. #include <iostream>
using namespace std;
int main(int argc, char** argv)
{
int a,b,c;
cout<<"Input a: ";
cin>>a;
cout<<"Input b: ";
cin>>b;
cout<<"Input c: ";
cin>>c;
if(a==b or a==c)
{
cout<<"Yes!"<<endl;
}
else if(b==a or b==c)
{
cout<<"Yes!"<<endl;
}
else if(c==a or c==b)
{
cout<<"Yes!"<<endl;
}
else
{
cout<<"Oops!"<<endl;
}
}
3. #include <iostream>
using namespace std;
int main(int argc, char** argv)
{
setlocale(LC_ALL, "Russian");
int a;
cout<<"Input a: ";
cin>>a;
switch(a)
{
case 1:
case 2:
case 3:
cout<<"Íèçêèé!"<<endl;
break;
case 4:
case 5:
case 6:
cout<<"Ñðåäíèé!"<<endl;
break;
case 7:
case 8:
case 9:
cout<<"Äîñòàòî÷íûé!"<<endl;
break;
case 10:
case 11:
case 12:
cout<<"Âûñîêèé!"<<endl;
break;
default:
cout<<"Error!"<<endl;
break;
}
}
4. #include <iostream>
using namespace std;
int main(int argc, char** argv)
{
int a, a1, a2, a3, a4, a5, a6;
cout<<"Input a: ";
cin>>a;
a1=a/1000;
a2=a/100%10;
a3=a%100/10;
a4=a%10;
a5=a1;
a6=a3;
if(a5>a1 && a6>a3)
{
cout<<"Number more"<<endl;
}
}
Вроде так
Объяснение:
