Как решить уравнение с модулем/4x=2,5/​

15 и 8
15 = 3 * 5 * 1
8 = 2³ * 1
НОД (15 и 8) = 1 взаимно простые числа
НОК (15 и 8) = 3 * 5 * 2³ = 15 * 8 = 120

70 и 30
70 = 2 * 5 * 7 * 1
30 = 2 * 3 * 5 * 1
НОД (70 и 30) = 2 * 5 * 1 = 10
НОК (70 и 30) = 2 * 3 * 5 * 7 * 1 = 210

85 и 17
85 = 5 * 17 * 1
17 = 1 * 17
НОД (85 и 17) = 17
НОК (85 и 17) = 5 * 17 = 85

100 и 25
100 = 2 * 2 * 5 * 5 * 1 = 2² * 5² * 1
25 = 5 * 5 * 1 = 5² * 1
НОД (100 и 25) = 5 * 5 = 25
НОК (100 и 25) = 2² * 5² = 100

75 и 20
75 = 1 * 3 * 5²
20 = 1 * 5 * 2²
НОД (75 и 20) = 5
НОК (75 и 20) = 3 * 5² * 2² = 300

36 и 24
36 = 1* 2² * 3²
24 = 1 * 2³ * 3
НОД (36 и 24) = 2² * 3 = 12
НОК (36 и 24) = 2³ * 3² = 72

(6 1/8 -1,75)/(9-2,2*(5 6/11-3,5))*1 2/7=1 1/4
1)6 1/8-1,75=6 1/8-1 75/100=6 1/8-1 3/4=49/8-7/4=35/8
2)5 6/11-3 5/10=5 6/11-3 1/2=61/11-7/2=(122-77)/22=45/22
3)45/22*2 1/5=45/22*11/5=9/2=4 1/2
4)9-4 1/2=4 1/2
5)35/8:9/2=35/8*2/9=35/36
6)35/36*1 2/7=35/36*9/7=5/4=1 1/4

(3 5/6-1 2/15)*5/9+((1/20+0,24)*8 1/3-1 1/6)*2=4
1)3 5/6-1 2/15=23/6-17/15=(115-34)/30=81/30=2 7/10
2)2 7/10*5/9=27/10*5/9=3/2=1 1/2
3)1/20+0,24=1/20+24/100=5/100+24/100=29/100
4)29/100*8 1/3=29/100*25/3=29/12
5)29/12-1 1/6=29/12-7/6=15/12=1 1/4
6)5/4*2=10/4=2 1/2
7)1 1/2+2 1/2=4