5*(х-2)+2*(3-х)=12 12(х-2)+(-4+х)=0 -(2-х)+3*(2х-3)=2 - вопрос №72439265223121224023232232110 от Xom9l4ok 17.11.2021 05:57

Question

Математика: 5*(х-2)+2*(3-х)=12 12(х-2)+(-4+х)=0 -(2-х)+3*(2х-3)=2 2*(3-х)-21*(х-1)=0

Xom9l4ok · Answer

5*(х-2)+2*(3-х)=125х-10+6-2х=123х-4=123х=12+43х=16х=16/3х=5 1/312(х-2)+(-4+х)=012х-24-4+х=013х-28=013х=0+2813х=28х=28/13х=2ц2/13-(2-х)+3*(2х-3)=2-2+х+6х-9=27х-11=27х=2+117х=13х=13/7х=1ц6/72*(3-х)-21*(х-1)=06-2х-21х+21=027-23х=023х=27-0х=27/23х=1ц4/23...