1! 1! 1! 1! (5 целых 5/7 * 3/8 - 5 целых 1/4 : - вопрос №7780930111155738514733728 от Azamatovna11 04.05.2020 03:28

Question

Алгебра: 1! 1! 1! 1! (5 целых 5/7 * 3/8 - 5 целых 1/4 : 7): 3+3 целых 7/28

Azamatovna11 · Answer

(1 1/7-23/49):22/147-(0,6:3 3/4)* 2 1/2+3,75:1 1/2):2,2=
=(33/49:22/147-(0,6:3 3/4)* 2 1/2+3,75:1 1/2):2,2=
=(33/49:22/147-4/25* 2 1/2+3,75:1 1/2):2,2=
=(4 1/2-4/25* 2 1/2+3,75:1 1/2):2,2=
=(4 1/2-2/5+3,75:1 1/2):2,2=
=(4 1/2-2/5+2 1/2):2,2=
=(4 1/10+2 1/2):2,2=
=1 3/5:2,2=
=8/11

1 1/7-23/49=8/7-23/49=56/49-23/49=33/49
0,6:3 3/4=6/10:3 3/4=3/5:15/4=3/5*4/15=12/75=4/25
33/49:22/147=33/49*147/22=3/1*3/2=9/2=4 1/2
4/25* 2 1/2=4/25*5/2=2/5
3,75:1 1/2=3 75/100:1 1/2=3 3/4:1 1/2=15/4:3/2=15/4*2/3=5/2=2 1/2
4 1/2-2/5=9/2-2/5=45/10-4/10=41/10=4 1/10
4 1/10+2 1/2=41/10+5/2=41/10+25/10=16/10=1 6/10=1 3/5
1 3/5:2,2=1 3/5:2 2/10=1 3/5:2 1/5=8/5:11/5=8/5*5/11=8/11